Question #c799c

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Question #c799c

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Answer 1 · 2017-03-22T00:43:57

Copper(II) chloride.

Explanation:

Copper's symbol is $Cu$ $"Cu"$ and chlorine's symbol is $Cl$ $"Cl"$ . Copper is a transition metal, so its charge can vary. Because of this variance, the copper cation needs to have the $(I I)$ $(II)$ after it.

The $I I$ $II$ is roman numerals for positive two, or $+ 2$ $+2$ . And lastly, because the chloride anion is $- 1$ $-1$ , and the copper cation $+ 2$ $+2$ , there must be two chlorines, making ${CuCl}_{2}$ $"CuCl"_2$ .

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