Question #0dfbd

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Question #0dfbd

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Answer 1 · 2017-03-22T01:30:09

Quite easy. Follow the steps below.

Explanation:

In a scenario like this, assume you have $100 g$ $100g$ of the compound.

So for each element, the percent is the total percent of $100 g$ $100g$ .

$N a = 35.4 g$ $Na = 35.4 g$
$A s = 39.1 g$ $As = 39.1 g$
$O = 25.0 g$ $O = 25.0 g$

Now, you will convert grams to moles for each element. Find the molar mass of each element from the periodic table and plug in.

$N a = \frac{35.4 g}{1} \cdot \frac{1 m o l}{23 g} = 1.5 m o l$ $Na = (35.4 g)/1 * (1 mol)/(23g) = 1.5 mol$
$A s = \frac{39.1 g}{1} \cdot \frac{1 m o l}{75 g} = 0.5 m o l$ $As = (39.1g)/1 * (1 mol)/(75g) = 0.5 mol$
$O = \frac{25.0 g}{1} \cdot \frac{1 m o l}{16 g} = 1.5 m o l$ $O = (25.0 g)/1 * (1 mol)/(16g) = 1.5 mol$

Now, divide every answer by the smallest number, which in this case is 0.5.

$\frac{1.5 m o l}{0.5 m o l} = 3$ $(1.5 mol)/(0.5mol) = 3$

$\frac{0.5 m o l}{0.5 m o l} = 1$ $(0.5 mol)/(0.5mol) = 1$

$\frac{1.5 m o l}{0.5 m o l} = 3$ $(1.5 mol)/(0.5mol) = 3$

These numbers are going to give you the ratios of the elements in the compound to give you an empirical formula.

$N a_{3} A s_{1} O_{3}$ $Na_3As_1O_3$

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Question #0dfbd

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