Question #d2faf
1 Answer
Mar 22, 2017
Explanation:
#5ixxbi#
#=5xxixxbxxi#
#=5xxbxxixxi#
#=5bxxi^2#
#=5bi^2# If we are dealing with
#color(blue)"complex numbers"#
#"then " i^2=(sqrt(-1))^2=-1#
#rArr5bi^2#
#=5bxx(-1)#
#=-5b#