Question #bdced

1 Answer
sjc
Mar 23, 2017

#T=2g N, " & " a=g/3 ms^(-2)#

Explanation:

we use Newton's 2nd law on both particles and solve the

eqns simultaneously

# **m_1** #

#T=6a#

# **m_2** #

#3g-T=3a#

substitute for #T#

#3g-6a=3a#

#9a=3g#

#a=g/3 ms^(-2)#

#:. T=6xxg/3=2g N#

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