Question

Question #209a9

Answer 1

Use the product rule :

`dy/dx= (f(x)g(x))'=f'(x)g(x)+f(x)g'(x)`

Explanation:

Use the product rule :

`dy/dx= (f(x)g(x))'=f'(x)g(x)+f(x)g'(x)`

let `f(x) = e^(3x) and g(x) = sin(4x)`, then it follows that `f'(x) = 3e^(3x) and g'(x)=4cos(4x)`

`dy/dx=(3e^(3x))(sin(4x))+(e^(3x))(4cos(4x))`