Question

A `0.20*g` mass of gas occupies a `0.200*L` volume at one atmosphere, and `300*K`. What is the molar mass of the gas?

Answer 1

`"Molar mass"` `=` `24.6*g*mol^-1`

Explanation:

We use the Ideal Gas Equation.......

`PV=nRT`

And thus `n="Mass"/"Molar Mass"=(PV)/(RT)`

And so, `"Molar Mass"=("Mass"xxRT)/(PV)`

`=(0.20*gxx0.0821*cancelL*cancel(atm)*cancel(K^-1)*mol^-1xx300*cancelK)/(1*cancel(atm)xx0.200*cancelL)`

`=24.6*g*mol^-1`. I think this is dimensionally correct, however, it does not correspond to a gas I can think of right now.........