Question #27266

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Question #27266

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Answer 1 · 2017-03-26T22:04:47

Yes

Explanation:

When diluting a solution with distilled water, $M_{1} V_{1} = M_{2} V_{2}$ $M_1V_1=M_2V_2$ where $M_{1}$ $M_1$ and $V_{1}$ $V_1$ are the molarity and volume of the concentrated solution and $M_{2}$ $M_2$ and $V_{2}$ $V_2$ are the molarity and volume of the dilute solution.

In this situation, $M_{1} = 1.0247 M$ $M_1=1.0247"M"$ , $V_{1} = 25 mL$ $V_1=25"mL"$ , and $V_{2} = 250 . mL$ $V_2=250."mL"$ . Rearranging the equation to solve for $M_{2}$ $M_2$ gives $M_{2} = \frac{M_{1} V_{1}}{V_{2}}$ $M_2=(M_1V_1)/V_2$ .

Plugging in the known values, we have $M_{2} = \frac{(1.0247 M) (25 mL)}{(250 . mL)}$ $M_2=((1.0247"M")(25"mL"))/((250."mL"))$ , and solving that gives $M_{2} = 0.10247 M$ $M_2=0.10247"M"$

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Question #27266

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