Question #18491

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Answer 1 · 2017-03-27T06:54:55

The answer is $(a)$ $(a)$

$∣ ∣ ∣ \to A ∣ ∣ ∣ = 44$ $|vecA|=44$

$∣ ∣ ∣ \to B ∣ ∣ ∣ = 16$ $|vecB|=16$

$phi=30º$

The vector product is

$|vecC|=|vecA|*|vecB|*sinphi$

$=44*16*sin30º$

$=44*16*1/2=44*8=352$

$vecC$ is perpendicular to $vecA$ and $vecB$