Question #65e73

1 Answer
Mar 28, 2017

68.4 litres

Explanation:

Assuming all oxygen atoms here are O-16 and that 1 mol of any gas at room temperature and pressure is 24dm^3,

M_r=("mass of gas")/(A_r), where M_r is molar mass and A_r is atomic mass

M_r=45.6/(16*2)=2.85 mol (bearing in mind oxygen gas in in the O_2 state)

Therefore, the volume of oxygen is:

V_(O_2)=2.85 mol*24dm^3=68.4dm^3=68.4 l