Question #092ca

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Question #092ca

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Answer 1 · 2017-04-18T06:53:28

The linear speed is $= 48.75 m s^{- 1}$ $=48.75ms^-1$
The centripetal acceleration is $= 31.69 m s^{- 2}$ $=31.69ms^-2$
The tangential acceleration is $= 17.25 m s^{- 2}$ $=17.25ms^-2$

Explanation:

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radius is $r = 75 m$ $r=75m$

angular speed is $ω = 0.65 r a d s^{- 1}$ $omega=0.65rads^-1$

angular acceleration is $α = 0.23 r a d s^{- 2}$ $alpha=0.23rads^-2$

The linear speed is

$v = ω r$ $v=omega r$

$= 0.65 \cdot 75 = 48.75 m s^{- 1}$ $=0.65*75=48.75ms^-1$

The centripetal acceleration is

$a_{c} = \frac{v^{2}}{r} = ω^{2} r$ $a_c=v^2/r=omega^2r$

$= 0.65 \cdot 0.65 \cdot 75 = 31.69 m s^{- 2}$ $=0.65*0.65*75=31.69ms^-2$

The tangential acceleration is

$a_{t} = α r$ $a_t=alpha r$

$= 0.23 \cdot 75 = 17.25 m s^{- 2}$ $=0.23*75=17.25ms^-2$

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Question #092ca

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