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Answer 1 · 2017-03-29T19:57:54

A 0.10 mol/L aqueous solution of sodium nitrate has a pH of 7.00.

Sodium nitrate is the salt formed by the reaction of nitric acid with sodium hydroxide.

The equation for the reaction is

$"HNO"_3 + "KOH" → "KNO"_3 + "H"_2"O"$

In ionic form, the equation is

$"H"^"+" + "OH"^"-" → "H"_2"O"$

$"HNO"_3$ is a very strong acid, so its conjugate base $"NO"_3^"-"$ is a very weak base.

It has no tendency to act as a base in aqueous solution.

In the same way, the conjugate acid of the strong base $"KOH"$ is $"K"^"+"$ .

$"K"^"+"$ has no tendency to act as a base in aqueous solution.

∴ The pH of a neutral solution is 7.00.