Question #63acc

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Question #63acc

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Answer 1 · 2017-03-29T17:37:54

0.22g

Explanation:

Converting the masses into $m o l$ $mol$ :
$C_{x} H_{y} + 0.22 O_{2} \to 0.44 C O_{2} + 0.9 H_{2} O$ $C_xH_y + 0.22O_2 -> 0.44CO_2 + 0.9H_2O$

$Mass of carbon, x = 0.44 \cdot (\frac{12}{44}) = 0.12 g$ $"Mass of carbon",x=0.44*(12/44)=0.12g$
$Mass of hydrogen, y = 0.9 \cdot (\frac{2}{18}) = 0.1 g$ $"Mass of hydrogen",y=0.9*(2/18)=0.1g$

Hence,
$Mass of hydrocarbon = 0.12 + 0.1 = 0.22 g$ $"Mass of hydrocarbon"=0.12+0.1=0.22g$

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Question #63acc

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