Question #8f1a7

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Question #8f1a7

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Answer 1 · 2017-03-30T17:14:03

$f (3) = 4$ $f(3) = 4$

Explanation:

$f (x) = \frac{1 + x^{- 1}}{x^{- 1}} = \frac{1 + \frac{1}{x}}{\frac{1}{x}} = \frac{\frac{x}{x} + \frac{1}{x}}{\frac{1}{x}} = \frac{\frac{1 + x}{x}}{\frac{1}{x}}$ $f(x) = (1+x^-1)/(x^-1) = (1+1/x)/(1/x) = (x/x + 1/x)/(1/x) = ((1+x)/x)/(1/x)$
$= (\frac{1 + x}{x}) \cdot (\frac{x}{1}) = 1 + x$ $= ((1+x)/x) * (x/1) = 1 + x$

$f (3) = 1 + 3 = 4$ $f(3) = 1 + 3 = 4$

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