What is the molar quantity of a gas at 742*mm*Hg742mmHg pressure, at 298.0*K298.0K temperature, confined to a volume of 6.0*L6.0L?

1 Answer
Mar 30, 2017

n=0.240*moln=0.240mol

Explanation:

We use the old ideal gas equation, i.e. PV=nRTPV=nRT

n=(PV)/(RT)=((742*cancel(mm*Hg))/(760*cancel(mm*Hg*atm^-1))xx6.0*cancelL)/(0.0821*cancel(L*atm*K^-1)*mol^-1xx298.0*cancelK)

=0.240*mol

What mass of HC-=N is present? Would you expect HC-=N to behave ideally? Why or why not? What hazards would be associated with this experiment?

Note the dimensional consistency of our calculation. We sought an answer in "moles"; the calculation gave us an answer in "moles" or at least 1/(mol^-1)=1/(1/(mol))=mol, so perhaps we are doing something right (for once!).

The key knowledge is the idea that 1*atm will support a column of mercury that is 760*mm high. And thus we may use a unit of length, the height of a mercury column, to give a useful and reproducible measurement of pressure.

Note that these days, mercury columns are a bit of a rarity. Has your teacher shown you a mercury column?