Question

Question #d33e2

Answer 1

`V` = `14.47 L`

Explanation:

No. of moles of `CO_2` = `28.45` g/`44` g.mol-1 = `0.646` moles

Ideal gas equation
`PV` =`nRT`
`V` = (`nRT`)/ `P`
`V` = (`0.646` moles x `0.08206` L. atm/ mol.K x `273` k)/`1`atm = `14.47` L