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Answer 1 · 2017-09-25T19:47:45

$4$ $4$

$y = 2.2 x + 10$ $y=2.2x+10$ is the equation of the least squares regression line.

$r e s i d u a l = Y_{o} b s - Y_{p} r e d$ $residual = Y_ obs -Y_pred$ , this is the formula we use to find the residual.

$y_{o} b s$ $y_obs$ means the value of $y$ $y$ that you found or observed from the scatter graph.

$Y_{p} r e d$ $Y_pred$ means the value of $y$ $y$ that you will find using the equation of the least squares regression line.

The point given is $(5, 25)$ $(5,25)$

$x = 5$ $x=5$

$y_{o} b s = 25$ $y_obs = 25$

(Using equation) $Y_{p} r e d = 2.2 \times 5 + 10$ $Y _ pred = 2.2 ×5+10$
$= 21$ $=21$

Residual $= 25 - 21$ $= 25-21$
$= 4$ $= 4$