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Question #91a05

1 Answer

Nov 15, 2017

The potential energy is $= 0.0045 J$ $=0.0045J$

Explanation:

The maximum potential energy is when the spring is fully compressed

The spring constant is $k = 10 N m^{- 1}$ $k=10Nm^-1$

The displacement is $x = 0.03 m$ $x=0.03m$

The potential energy is $E_{p} = \frac{1}{2} k x^{2} = \frac{1}{2} \cdot 10 \cdot {0.03}^{2} = 0.0045 J$ $E_p=1/2kx^2=1/2*10*0.03^2=0.0045J$

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