Question #94672

1 Answer

The new pressure "P"_2=420\ "kPa"

Explanation:

The general equation of ideal gases follows the following form:
("P"_1*"V"_1)/("R"*"T"_1)=("P"_2*"V"_2)/("R"*"T"_2) .......... (1)
At constant temperature, "T"_1 = "T"_2. Thus, the equation Form (1) is reduced to: "P"_1*"V"_1="P"_2*"V"_2, which will lead to the following form:
"P"_2=("P"_1*"V"_1)/"V"_2 ................. (2)
"P"_2=(42\ "kPa"*20\ "L")/(2\ "L")
So, "P"_2=420\ "kPa"
With kind regards: Mamdouh Younes