Question

Question #ed919

Answer 1

`LHS=(Sin(90-x))/(1+sinx)+cosx/(1-cos(90-x))`

`=cosx/(1+sinx)+cosx/(1-sinx)`

`=(cosx(1-sinx)+cosx(1+sinx))/((1+sinx)(1-sinx))`

`=(cosx(1-sinx+1+sinx))/(1-sin^2x)`

`=(2cosx)/cos^2x`

`=2/cosx`

`=2secx=RHS`

Proved