Question #5c5a5

1 Answer
Oct 17, 2017

a) Phi_B=0.0306 Wb
b) Phi_B=0.0184 Wb

Explanation:

Magnetic flux is calculated as Phi_B = B*A*costheta
where theta is the angle between the direction of the field and the normal to the surface enclosed by the loop.

In this case, the field is 0.230 T, and the area is A=pi*r^2= 0.0133 m^2

(Note the necessary change from cm to m.)

So, if theta = 0°, as in part a of your question (If the circle lies in the x-y plane, the normal points perpendicular to the plane - in the direction of the z-axis.)

Phi_B= (0.230*0.0133)*cos(0°)=0.00306 Wb (webers)

And in part b, where theta= 53.1°

Phi_B= (0.230*0.0133)*cos(53.1°)=0.00184 Wb