In which interval the function #f(x)=sqrt(x^2+8)-x# is a decreasing function?
1 Answer
Apr 4, 2017
Explanation:
Intervals of increasing of a function are those where
Here
and
#=x/sqrt(x^2+8)-1#
#=(x-sqrt(x^2+8))/sqrt(x^2+8)#
It is apparent that as
i.e. for all
Hence,
graph{sqrt(x^2+8)-x [-8.125, 11.875, -3.28, 6.72]}