Question #27b41 Chemistry Acids and Bases pH calculations 1 Answer David L. Apr 4, 2017 #1.86*10^-5 M# Explanation: #pH=-log[H^+]# re-write, #[H^+]=10^(-pH)# = #10^(-4.73)# = #1.86*10^-5 M# Answer link Related questions How do you determine ph of a solution? How do you determine pH at an equivalence point? How do you determine pH from molarity? What does alkalinity mean? What is a base? How do acid base indicators change color? What is a neutral pH? How does alkalinity affect pool water? Why is pH important in drinking water? How can I calculate the pH of a solution? See all questions in pH calculations Impact of this question 1486 views around the world You can reuse this answer Creative Commons License