Question #5c77f

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Answer 1 · 2017-04-04T09:25:01

Option (5)

Formula to get the resolved part of a vector $vecV$ along the direction making an angle $theta$ with it is given by

$vecV_"resolved part"=vecVcostheta$

$vecA$ makes an angle $theta=0^@$ with the X-axis and it makes an angle $theta=90^@$ with the Y-axis.

So its resolved part along X-axis

$vecA_x=vecAcos0^@$

And its resolved part along Y-axis

$vecA_y=vecAcos90^@$

Again $vecB$ makes an angle $theta=(180^@-60^@)$ with the X-axis and it makes an angle $theta=30^@$ with the Y-axis.

So its resolved part along X-axis

$vecB_x=vecBcos(180^@-60^@)=-Bcos60^@$

And its resolved part along Y-axis

$vecB_y=vecBcos30^@$