Question #631d7

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Question #631d7

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Answer 1 · 2017-04-18T16:18:55

$6 . ¯ 6 c m$ $6.bar6cm$

Explanation:

When two thin convex lenses of focal length $f_{1} and f_{2}$ $f_1 and f_2$ are placed at a distance $d$ $d$ apart, the equivalent focal length $F$ $F$ of the system is given by the expression

$F = \frac{f_{1} \cdot f_{2}}{f_{1} + f_{2} - d}$ $F=(f_1cdotf_2)/(f_1+f_2-d)$

Inserting given values we get
$F = \frac{20 \cdot 5}{20 + 5 - 10}$ $F=(20cdot5)/(20+5-10)$
$F = \frac{100}{15} = 6 . ¯ 6 c m$ $F=100/15=6.bar6cm$

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Question #631d7

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