Question #67d90

1 Answer
A.Raz
Apr 10, 2017

7540 torr

Explanation:

K_p =(P_(NOBr) )^2/[(P_(Br_2))(P_(NO))^2
The exponents were determined from the coefficients in front of each product or reactant. Also the equilibrium constant is (Products)/(Reactants) as can be seen with how the equilibrium constant is written. Now we just plug in and solve for the partial pressure of NOBr

28.4 =(P_(NOBr) )^2/[(154)(114)^2]

P_(NOBr)=7539.185 torr

Rounded according to significant figures: 7540 torr

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