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Answer 1 · 2017-04-08T11:23:29

The ratio is $= 2.45$ $=2.45$

The period of a pendulum is

$T_{e} = 2 π \sqrt{\frac{l}{g_{e}}}$ $T_e=2pisqrt(l/g_e)$

On the moon the period will be

$T_{m} = 2 π \sqrt{\frac{l}{g_{m}}}$ $T_m=2pisqrt(l/g_m)$

The ratio will be

$\frac{T_{m}}{T_{e}} = \frac{\sqrt{\frac{l}{g_{m}}}}{\sqrt{\frac{l}{g_{e}}}}$ $T_m/(T_e)=sqrt(l/g_m)/sqrt(l/g_e)$

$= \sqrt{\frac{g_{e}}{g_{m}}}$ $=sqrt(g_e/g_m)$

$= \sqrt{\frac{9.8}{1.63}}$ $=sqrt(9.8/1.63)$

$= 2.45$ $=2.45$