Question #21b37
1 Answer
Here's how you can do that.
Explanation:
Parts per million is a measure of the number of parts of solute present for every
So every time you have a
In your case, you have the volume of the solution. If you're dealing with an aqueous solution, i.e. you have water as the solvent, then you can use its density to find the total mass of the solution.
Let's say that you have
Assuming a density of
#1 color(red)(cancel(color(black)("L"))) * (10^3color(red)(cancel(color(black)("mL"))))/(1color(red)(cancel(color(black)("L")))) * "1 g"/(1color(red)(cancel(color(black)("mL")))) = 10^3# #"g"#
Now, this solution contains
#10^3 color(red)(cancel(color(black)("g solution"))) * overbrace("15 g solute"/(10^6color(red)(cancel(color(black)("g solution")))))^(color(blue)("= 15 ppm")) = 15 * 10^(-3)# #"g solute"#
You can thus say that if you have
#15 * 10^(-3) color(red)(cancel(color(black)("g"))) * "1 mg"/(10^(-3)color(red)(cancel(color(black)("g")))) = "15 mg"#
of solute in