Question #487ba
1 Answer
Explanation:
The equation of a line in
#color(blue)"slope-intercept form"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))#
where m represents the slope and b, the y-intercept.
#"Rearrange " 3x-2y=8" into this form"# subtract 3x from both sides.
#cancel(3x)cancel(-3x)-2y=-3x+8#
#rArr-2y=-3x+8#
#"divide ALL terms by "-2#
#(cancel(-2) y)/cancel(-2)=-3/(-2)x+8/(-2)#
#rArry=3/2x-4larrcolor(red)" in slope-intercept form"#
#rArr"slope "=m=3/2" and y-intercept "=b=-4# To graph the line using slope and y-intercept.
#• " Plot the point "(0,-4)larrcolor(red)"from y-intercept"#
#• m=3/2=("change in y")/("change in x")#
#rArr(0+2,-4+3)to(2,-1)larrcolor(red)" second point"#
#"A third point is useful when graphing a line"#
#"Repeat the process"#
#rArr(2+2,-1+3)to(4,2)larrcolor(red)" third point"#
#"Plot all 3 points and draw a straight line through them"#
graph{3/2x-4 [-11.25, 11.25, -5.62, 5.62]}
