How is #C_6H_11Br# made?

1 Answer
anor277
Apr 8, 2017

You might want to qualify this question. At the moment, I don't know what you ask.

Explanation:

Cyclohexane, #C_6H_12#, has one, so-called, #"degree of unsaturation"#. We refer to the saturated alkane, i.e. #C_nH_(2n+2)#. The ring junction in cyclohexanol reduces the hydrogen count by 2.

As to how to make #"cyclohexyl bromide"# from #"cyclohexane"#; the standard means is to halogenate the cycloalkane with #"NBS"# under UV light:

#C_6H_12 + Br_2 stackrel(hnu)rarr C_6H_11Br + HBr#

Hydrolysis of the cyclohexyl bromide would yield the alcohol.

Anyway, it's over to you..........

Related questions
See all questions in Introduction to Reactions and Mechanisms
Impact of this question
1236 views around the world
You can reuse this answer
Creative Commons License