Question #fba72
1 Answer
Here's what I got.
Explanation:
The question wants you to figure out how many milligrams of ascorbic acid, also known as Vitamin C, are present in
The idea here is that you're diluting the initial solution twice, first when you make its total volume to
The initial solution contains
You can now say that the solution contains
You can thus use the composition of the solution after the first dilution as a conversion factor to help you determine the mass of ascorbic acid present in the
#25 color(red)(cancel(color(black)("mL solution"))) * "0.25 g ascorbic acid"/(250 color(red)(cancel(color(black)("mL solution")))) = "0.0120 g ascorbic acid"#
You then take this sample and add enough water to gets its total volume to
Consequently,
#100 color(red)(cancel(color(black)("mL solution"))) * "0.0120 g ascorbic acid"/(250 color(red)(cancel(color(black)("mL solution")))) = "0.0048 g ascorbic acid"#
Convert this to milligrams
#0.0048 color(red)(cancel(color(black)("g"))) * (10^3color(white)(.)"mg")/(1color(red)(cancel(color(black)("g")))) = "4.8 mg"#
Therefore, you can say that the final solution contains
#color(darkgreen)(ul(color(black)("5 mg ascorbic acid/100 mL solution")))#
The answer is rounded to one significant figure.