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Question #ba724

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kingsito · EZ as pi

Apr 10, 2017

graph{y=-8x-1 [-10, 10, -5, 5]}
slope of $- \frac{8}{1}$ $-8/1$
y-int $= (0, - 1$ $= (0,-1$ )

Explanation:

$- 1$ $-1$ is the intercept on the y axis, which the line passes through.
$- 8$ $-8$ is the slope of the line.

In this case, since $m = - 8 = - \frac{8}{1}$ $m =-8=-8/1$ ,

from $(0, - 1)$ $(0,-1)$ you must move down $8$ $8$ units and then go right $1$ $1$ unit to give a negative slope.

The the rule of slope is $\frac{rise}{run}$ $"rise"/" run"$ or $\frac{change in y}{change in x}$ $"change in y"/"change in x"$ .

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