Question

Question #e43d3

Answer 1

`i^i = e^( - pi/2)`

Explanation:

Euler's Formula:

`e^(i x) = cos x + i sin x`

`implies i = cos (pi/2) + i sin (pi/2) = e^( i pi/2)`

`i^i = (e^( i pi/2))^i = e^( i cdot i pi/2) = e^( - pi/2)`