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Answer 1 · 2017-04-11T16:05:41

$X-intercept= - 6, Y-intercept= 18, & Z-intercept= - 9 .$ $" X-intercept="-6," Y-intercept="18," & Z-intercept="-9.$

Let us realise that the given eqn. represents a plane, say $π .$ $pi.$

The eqn. of a plane having the intercepts $a, b, c$ $a,b,c$ on the Axes, is,

$x/a+y/b+z/c=1................(ast).$

So, to determine the intercepts of $pi,$ let us convert in the $(ast)$ form.

$3x-y+2z=-18.$

$:. (3x-y+2z)/-18=1, i.e., x/-6+y/18+z/-9=1.$

$rArr" X-intercept="-6," Y-intercept="18," & Z-intercept="-9.$