Question

Question #004f2

Answer 1

0.56

Explanation:

1 molar solution =`"Number of moles of solute"/"Volume of solution"`
for Sugar
`C_(12)H_(22)O_(11)` molar mass=342`gm`
according to equation and information provided
`1=(3.42/342)/x`
where x is the volume of solution in `l`
`:.` the volume of solution is 0.01 `l`
which is 10 `ml`
`:.`10 gm of water .
moles of solute=`3.42/342=0.01`
moles of solution =`10/18=0.55`
`:.` the mole fraction of the solution is `0.01/(0.01+0.55)`