Question #17639

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Question #17639

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Answer 1 · 2017-04-12T22:27:49

I'll show you!

Explanation:

For convenience, I will use kPa rather than mmHg. But that is a mere preference (and I will walk you through the same calculations using mmHg in the second part):

You should already know the relationship between volume and pressure:

$V α \frac{1}{p}$ $Valpha1/p$

You may also know that:

$P_{1} V_{1} = P_{2} V_{2}$ $P_1V_1=P_2V_2$ <- This essentially means, that the initial conditions the final conditions

So, what do we know from the question?
$P_{1} = 100 k P a$ $P_1=100kPa$
$V_{1} = 2.5 d m^{3}$ $V_1=2.5dm^3$ (i.e. L)
$P_{2} = 66.66 k P a$ $P_2=66.66kPa$

Hence:
$100 \cdot 2.5 = 66.66 \cdot V_{2}$ $100*2.5=66.66*V_2$
$V_{2} = 3.75 d m^{3}$ $V_2=3.75dm^3$ (i.e. L)

The same thing is also true if you use mmHg:

$P_{1} = 750 m m H g$ $P_1=750mmHg$
$V_{1} = 2.5 d m^{3}$ $V_1=2.5dm^3$ (i.e. L)
$P_{2} = 500 m m H g$ $P_2=500mmHg$

Hence:
$750 \cdot 2.5 = 500 \cdot V_{2}$ $750*2.5=500*V_2$
$V_{2} = 3.75 d m^{3}$ $V_2=3.75dm^3$ (i.e. L)

Hope it helped :)

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Question #17639

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