Question

Question #17639

Answer 1

I'll show you!

Explanation:

For convenience, I will use kPa rather than mmHg. But that is a mere preference (and I will walk you through the same calculations using mmHg in the second part):

You should already know the relationship between volume and pressure:

`Valpha1/p`

You may also know that:

`P_1V_1=P_2V_2` <- This essentially means, that the initial conditions the final conditions

So, what do we know from the question?
`P_1=100kPa`
`V_1=2.5dm^3` (i.e. L)
`P_2=66.66kPa`

Hence:
`100*2.5=66.66*V_2`
`V_2=3.75dm^3` (i.e. L)

The same thing is also true if you use mmHg:

`P_1=750mmHg`
`V_1=2.5dm^3` (i.e. L)
`P_2=500mmHg`

Hence:
`750*2.5=500*V_2`
`V_2=3.75dm^3` (i.e. L)

Hope it helped :)