Question #c05da

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Answer 1 · 2018-01-14T14:09:29

$y = - x + 6$ $y = -x+ 6$ which is in the form $y = m x + c$ $y = mx + c$

Slope of line L1 is $m_{L} = tan (45) = 1$ $m_L = tan (45) = 1$

Slope of the line L1 perpendicular to L $= - \frac{1}{m_{L}} = - 1$ $= -1/(m_L) = -1$

Equation of L1 with slope -1 and passing through point (6,0) is

$y - y 1 = m (x - x 1)$ $y - y1 = m (x - x1)$

$y - 0 = - 1 \cdot (x - 6)$ $y - 0 = -1 * (x - 6)$

$y = - x + 6$ $y = -x + 6$ which is in the form $y = m x + c$ $y = mx + c$