Question

Question #c5cb2

Answer 1

By the problem the following gaseous reaction is occuring in closed, rigid vessel at constant temperature.

`W(g)+X(g)->Y(g)+Z(g)`

The stoichiometric ratio of number of moles of reactants and prducts is

`W(g):X(g):Y(g):Z(g)=1:1:1:1`

The volume and temperature remaining constant the partial pressures of the component gases are proportional to their number of moles.

The initial partial pressures of `W(g) and X(g)` are 1.2 atm and 1.6 atm respectively.
And the initial partial pressures of `Y(g) and Z(g)` are 0 atm.

If the partial pressure of `W(g)` is decreased to 1atm then the 0.2atm decrease is due to its taking part in the reaction.
So the decrease in pressure of `X(g)` will also be 0.2 atm.

But pressures of each of #Y(g) and Z(g) # will be inreased to 0.2atm as the interacting mole ratio is `1:1:1:1`