Question

Question #20e44

Answer 1

`oo`

Explanation:

`(x^2+sin^2x+xsinx)/sin^3x = 1/sinx(x^2/sin^2x+1+x/sinx)`

so

`lim_(x->0)(x^2+sin^2x+xsinx)/sin^3x=lim_(x->0)(1/sinx)lim_(x->0)(x^2/sin^2x+1+x/sinx)=1/0(3)=oo`