Question

Question #3828f

Answer 1

See below.

Explanation:

`a x^2+bx+c = a(x^2+b/ax+c/a)`

and now

`x =1/2 (-b/apm sqrt((b/a)^2-4(c/a)))`

or

`ax^2+bx+c=a(x+b/(2a)+1/2sqrt((b/a)^2-4(c/a)))(x+b/(2a)-1/2sqrt((b/a)^2-4(c/a)))`

or

`ax^2+bx+c=a(x+b/(2a)+1/(2absa)sqrt(b^2-4ac))(x+b/(2a)-1/(2absa)sqrt(b^2-4ac))`