Question #6b172

1 Answer
Jun 2, 2017

We're asked to find the liters of "Cl"_2Cl2 occupied by 6.76.7 "g Cl"_2g Cl2.

What we can do here is calculate the number of moles of chlorine using the molar mass of "Cl"_2Cl2, 70.90"g"/"mol"70.90gmol:

6.76.7 cancel("g Cl"_2)((1"mol Cl"_2)/(70.90cancel("g Cl"_2))) = 0.0945 "mol Cl"_2

At standard temperature and pressure, one mole of any gas occupies a volume of 22.41 "L". (from Avogadro's law). We can use this fact to convert from moles to liters:

0.0945cancel("mol Cl"_2)((22.41"L Cl"_2)/(1cancel("mol Cl"_2))) = color(red)(2.1) color(red)("L Cl"_2)