What are the formal oxidation numbers for the constituent atoms in $H - I$ $H-I$ ?

Question

What are the formal oxidation numbers for the constituent atoms in $H - I$ $H-I$ ?

1 Answer

Impact of this question

2561 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-19T05:10:28

We have $+ I H - - I I$ $stackrel(+I)H-stackrel(-I)I$

Explanation:

While electronegativity DECREASES down a Group, iodine is still an electronegative halogen. And thus in $H I (g)$ $HI(g)$ its oxidation state is $- I$ $-I$ .

Science

Math

Humanities

... and beyond

What are the formal oxidation numbers for the constituent atoms in $H - I$ $H-I$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

What are the formal oxidation numbers for the constituent atoms in H−IH-I?

1 Answer

Explanation:

Related questions

Impact of this question

What are the formal oxidation numbers for the constituent atoms in $H - I$ $H-I$ ?