0.013⋅dm3 of 0.100⋅mol⋅L−1 NaOH reacts completely with 0.010⋅dm3 HCl; what is the concentration of [HCl](aq)?

1 Answer
anor277
Apr 20, 2017

The stoichiometric equation is...........

Explanation:

NaOH(aq)+HCl(aq)→NaCl(aq)+H2O(l)

Sodium hydroxide and hydrogen chloride react with a 1:1 stoichiometry. And so we simply have to assess the molarity of the acid solution.

Moles of base = 0.100⋅mol⋅dm−3×0.013⋅dm3=1.30×10−3⋅mol.

Now this molar quantity was equimolar with the 0.010⋅dm3 volume of HCl(aq).

Concentration of HCl=1.30×10−3⋅mol0.010⋅dm−3=0.130⋅mol⋅dm−3

Note that 1⋅dm3=1×(10−1⋅m)3=10−3⋅m3=1⋅L as required. A cubic metre is a huge volume, and is equivalent to 1000⋅L.

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