Question #c9e57

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Question #c9e57

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Answer 1 · 2017-04-20T15:59:30

Because they can accept protons (= $H^{+}$ $H^+$ )

Explanation:

Example:
Iron(II) oxide does not ionize into $O H^{-}$ $OH^-$ ions, but it will accept protons from an acid.
$F e O + 2 H_{3} O^{+} \to F e^{2 +} + 3 H_{2} O$ $FeO+2H_3O^+ ->Fe^(2+) +3H_2O$
or more simply:
$F e O + 2 H^{+} \to F e^{2 +} + H_{2} O$ $FeO+2H^+ ->Fe^(2+)+H_2O$

Another one:
$N H_{3} + H_{2} O ⇌ N H_{4}^{+} + O H^{-}$ $NH_3+H_2OrightleftharpoonsNH_4^+ +OH^-$
Where $N H_{3}$ $NH_3$ snatches an $H^{+}$ $H^+$ from the water molecule, to leave an $O H^{-}$ $OH^-$ ion.

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Question #c9e57

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