Question #bde7e

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Question #bde7e

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Answer 1 · 2017-04-20T20:06:52

1.5 liters.

Explanation:

Use this equation: $P_{1} V_{1} = P_{2} V_{2}$ $" "P_1V_1 = P_2V_2$

$P_{1}$ $P_1$ = 109 kPa
$V_{1}$ $V_1$ = 3 L
$P_{2}$ $P_2$ = 218 kPa
$V_{2}$ $V_2$ = ??

$P_{1} V_{1} = P_{2} V_{2}$ $P_1V_1 = P_2V_2$
(109)(3) = (218)( $V_{2}$ $V_2$ )
(327) = (218)( $V_{2}$ $V_2$ )
$V_{2}$ $V_2$ = 1.5

Therefore the new volume would be 1.5 Liters.

(this equation can only be used if the temperature remains constant. if temperature, volume, and pressure are all changing, used the combined gas law: $\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$ $(P_1V_1)/T_1 = (P_2V_2)/T_2$ )

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