To completely combust a 5 mole quantity of glucose, how many moles of dioxygen are required?

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To completely combust a 5 mole quantity of glucose, how many moles of dioxygen are required?

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Answer 1 · 2017-04-21T07:51:32

Well first we write a stoichiometrically balanced equation...

$C_{6} H_{12} O_{6} (s) + 6 O_{2} (g) \to 6 C O_{2} (g) + 6 H_{2} O (l)$ $C_6H_12O_6(s) + 6O_2(g) rarr 6CO_2(g) + 6H_2O(l)$

Explanation:

Is this stoichiometrically balanced?

And thus, clearly, we require a 30 mole quantity of dioxygen gas for complete combustion of a 5 mole quantity of glucose. What masses do these quantities represent?

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To completely combust a 5 mole quantity of glucose, how many moles of dioxygen are required?

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Explanation:

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