Question #5018b

1 Answer
Apr 22, 2017

"16.0 g"16.0 g

Explanation:

STP conditions are usually given as a pressure of "1 atm"1 atm and a temperature of 0^@"C"0C. Under these conditions, 11 mole of any ideal gas occupies "22.4 L"22.4 L -> this is known as the molar volume of a gas at STP.

Using the molar volume of a gas at STP, you can calculate the number of moles of oxygen gas present in your sample

11.2 color(red)(cancel(color(black)("L"))) * "1 mole O"_2/(22.4color(red)(cancel(color(black)("L")))) = "0.50 moles O"_2

To convert this to grams, use the molar mass of oxygen gas

0.50 color(red)(cancel(color(black)("moles O"_2))) * "32.0 g"/(1color(red)(cancel(color(black)("mole O"_2)))) = color(darkgreen)(ul(color(black)("16.0 g")))

The answer is rounded to three sig figs, the number of sig figs you have for the volume of oxygen gas.