The Ksp values are of course available in the literature, and SHOULD have been included in the question.
Once we have Ksp values, then we can address the various solubility. For calcium chloride we approach this in this manner........
Ca(OH)2(s)⇌Ca2++2HO−
Now Ksp=[Ca2+][HO−]2.
And if we call the solubility of calcium chloride, S, then S=[Ca2+], and [Cl−]=2S (provided there is no extraneous source of calcium and chloride ions......)
So Ksp=S×(2S)2=4S3.
And S=3√Ksp4.
And so without Ksp we are at an impasse. Such calculations require prior measurement or reference to the literature data.
