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Question #e4a84

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qin · Stefan V.

Apr 25, 2017

(a) $2.31 \times 10^{10}$ $" "2.31 xx 10^10$

(b) $3.25 \times 10^{12}$ $" "3.25 xx 10^12$

Explanation:

Electrons are fundamental charges and each electron has a charge of $- 1.60 \cdot 10^{- 19} C$ $-1.60*10^(-19)C$ .

In each case, divide the charge required by this value and you will get the number of electrons needed.

(a) $\frac{- 3.70 \cdot 10^{- 9}}{- 1.6 \cdot 10^{- 19}} = 2.31 \cdot 10^{10}$ $(-3.70*10^(-9)) / (-1.6*10^(-19)) = 2.31*10^(10)$

(b) $\frac{0.520 \cdot 10^{- 6}}{- 1.6 \cdot 10^{- 19}} = 3.25 \cdot 10^{12}$ $(0.520*10^(-6)) / (-1.6*10^(-19)) = 3.25*10^(12)$

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