Question #5ca90

Question

Question #5ca90

1 Answer

Impact of this question

2149 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-26T13:52:41

$the receiver frequency is 9907.68 Hz.$ $"the receiver frequency is 9907.68 Hz."$

Explanation:

$v_{air} : velocity of sound in the air , v_{air} = 340 \frac{m}{s}$ $v_("air"):"velocity of sound in the air ,"v_("air")=340 " "m/s$

$v_{s} : velocity of source , v_{s} = 140 \frac{k m}{h r} = \frac{140.000}{3600} = 38.89 \frac{m}{s}$ $v_s:"velocity of source ,"v_s=140 (km)/(hr)=(140.000)/(3600)=38.89" "m/s$

$v_{r} : velocity of receiver , v_{r} = 150 \frac{k m}{h r} = \frac{150.000}{3600} = 41.67 \frac{m}{s}$ $v_r:"velocity of receiver ,"v_r=150" "(km)/(hr)=(150.000)/(3600)=41.67" "m/s$

$f_{s} : frequency of source , f_{s} = 10 k H z = 10000 H z$ $f_s:"frequency of source ,"f_s=10kHz=10000Hz$

$f_{r} : frequency of receiver$ $f_r:"frequency of receiver "$

$f_{r} = f_{s} \cdot \frac{v_{air} \pm v_{r}}{v_{air} \pm v_{s}}$ $f_r=f_s * (v_("air")+-v_r)/(v_("air")+-v_s )$

$since the distance between receiver and source increase,$ $"Since the distance between receiver and source increase,"$
$you should write the sign of v_{r} as negative and the sign of the v_{s} as positive.$ $"you should write the sign of " v_r " as negative and the sign of the " v_s " as positive."$

$f_{r} = f_{s} \cdot \frac{v_{air} - v_{r}}{v_{air} + v_{s}}$ $f_r=f_s *(v_("air")-v_r)/(v_("air")+v_s)$

$f_{r} = 10000 \cdot \frac{(340 - 41.67)}{(340 + 38.89)}$ $f_r=10000 *((340-41.67))/((340+38.89))$

$f_{r} = 9907.68 H z$ $f_r=9907.68 " "Hz$

Science

Math

Humanities

... and beyond

Question #5ca90

1 Answer

Explanation:

Related questions

Impact of this question