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Question #57781

1 Answer

Apr 26, 2017

3 moles of $O_{2}$ $O_2$ are needed; 6 moles of MgO are produced.

Explanation:

The balanced equation is

$2 M g + O_{2} \to 2 M g O$ $2Mg+O_2 rarr 2MgO$

We see that the ratio of Mg to $O_{2}$ $O_2$ is 2:1

This means you need twice as many moles of magnesium as oxygen, or if you prefer, half as much oxygen as magnesium.

Either way, the 6 moles of Mg require 3 moles of $O_{2}$ $O_2$ to react completely.

We will get 6 moles of $M g O$ $MgO$ , as the ratio between Mg and MgO is 2:2 (or 1:1).

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